2x^2-25x-450=0

Solution for 2x^2-25x-450=0 equation:

2x^2-25x-450=0

a = 2; b = -25; c = -450;
Δ = b2-4ac
Δ = -252-4·2·(-450)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-65}{2*2}=\frac{-40}{4}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+65}{2*2}=\frac{90}{4}
=22+1/2
$